Physics 9 Unit 4 MCQs Tests

In this post, we have prepared 3 MCQs tests of Federal Board Physics 9 Unit 4 MCQs Tests.

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Physics 9 Unit 4 MCQs Tests

Practice MCQs Test No 1

356

Class 9 Physics
Unit 4
Practice MCQs Test No 1

1 / 10

Forces that are parallel to each other and have the same direction are called:

Unparallel forces

Unlike parallel forces

Parallel forces

Like parallel forces

Same direction means like

and opposite direction means unlike

2 / 10

Head to tail rule is a:

Used for addition of forces

Used for vector addition

All are correct

Graphical method

3 / 10

Centre of gravity of a uniform triangular sheet lies at the point of intersection of its:

Diagonals

Medians              

Corners     

Lines   

4 / 10

The number of forces that can be added by head to tail rule is:

2

Any number

3

3

5 / 10

A body is in equilibrium when its:

Speed is uniform

Acceleration is zero

Acceleration is uniform

Speed and acceleration both are uniform

6 / 10

SI unit of torque is:

newton-meter

joule

meter per second

newton

Torque  =  Force × Moment arm

Torque   =  newton-meter

7 / 10

A point where the whole weight of the body appears to act vertically downward is called:

Centre of mass

Moment arm

Torque

Centre of gravity

Weight is related to gravity so correct answer is center of gravity.

8 / 10

Torque depends on:

Force  

Acceleration                  

Both Force and Moment arm

Moment arm

The formula of torque is:

Torque = Force ×  Moment arm

So torque depends on both Force and moment arm.

9 / 10

A body is said to be in equilibrium if:

Its velocity is not changing

Its velocity is changing

Its acceleration is not uniform

Its acceleration is uniform

10 / 10

A pencil just balanced at its tip is in ________.

Stable Equilibrium

Neutral Equilibrium

Unstable Equilibrium

Dynamic Equilibrium

Pencil will not come back to its previous position so it is unstable equilibrium.

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Practice MCQs Test No 2

223

Class 9 Physics
Unit 4
Practice MCQs Test No 2

Use formula   Fx = F Cos θ

1 / 10

If F=200N and θ=30°  with horizontal then what will be the value of F_x?

100 N

173.2 N 

200 N 

50 N 

Fx = F Cosθ

Fx = 200 × Cos 30°

Fx = 200 × 0.866

Fx = 173.2 N

2 / 10

When a body is in unstable equilibrium, its center of gravity:

remains at the same height

is at the lowest position

all are correct

is at its highest position

3 / 10

The number of perpendicular components of a force are:

2

3

4

1

There are two perpendicular components :

Horizontal component Fx

and vertical component Fy

4 / 10

The centre of gravity of triangular-shaped body is:

The point of intersection of altitudes

The point of intersection of its diagonals

The centre of triangle

The point of intersection of its medians

5 / 10

A racing car is made stable by:

Decreasing its mass

Decreasing its width

Increasing its speed  

Lowering its centre of gravity

For stable equilibrium center of gravity must be at the lowest position.

Find Fy

Force along x-axis means θ=0°

6 / 10

A force of 10 N is acting along x-axis. Its vertical component will be:

Zero

10 N

20 N

0.5 N

Fy = F Sin θ

Fy = 10 Sin 0°

Fy = 10 (0)  =   0 N

Use formula   Fy = F Sin θ

7 / 10

If F=200N and θ=30°  with horizontal then what will be the value of F_y?

100 N

173.2 N

50 N

200 N

Fy = F Sinθ

Fy = 200 × Sin 30°

Fx = 200 × 0.5

Fx = 100 N

8 / 10

When a body is in stable equilibrium, its center of gravity:

is at its highest position

remains at the same height

all are correct

is at the lowest position

9 / 10

When a body is in neutral equilibrium, its center of gravity:

is at its highest position

all are correct

is at the lowest position

remains at the same height

10 / 10

Two equal but unlike parallel forces having different line of action produce:

a torque

a couple

equilibrium

neutral equilibrium

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Challenge MCQs Test

347

---

Class 9 Physics
Unit 4
Full Chapter Challenge Test

Use formula   Fy = F Sin θ

1 / 20

If F=200N and θ=30°  with horizontal then what will be the value of F_y?

100 N

200 N

50 N

173.2 N

Fy = F Sinθ

Fy = 200 × Sin 30°

Fx = 200 × 0.5

Fx = 100 N

2 / 20

Head to tail rule is a:

All are correct

Used for addition of forces

Used for vector addition

Graphical method

3 / 20

The number of forces that can be added by head to tail rule is:

3

2

3

Any number

4 / 20

SI unit of torque is:

meter per second

joule

newton-meter

newton

Torque  =  Force × Moment arm

Torque   =  newton-meter

5 / 20

A pencil just balanced at its tip is in ________.

Unstable Equilibrium

Stable Equilibrium

Dynamic Equilibrium

Neutral Equilibrium

Pencil will not come back to its previous position so it is unstable equilibrium.

6 / 20

Torque depends on:

Both Force and Moment arm

Moment arm

Force  

Acceleration                  

The formula of torque is:

Torque = Force ×  Moment arm

So torque depends on both Force and moment arm.

7 / 20

The centre of gravity of triangular-shaped body is:

The point of intersection of its diagonals

The centre of triangle

The point of intersection of its medians

The point of intersection of altitudes

8 / 20

A body is in equilibrium when its:

Speed is uniform

Speed and acceleration both are uniform

Acceleration is zero

Acceleration is uniform

Find Fy

Force along x-axis means θ=0°

9 / 20

A force of 10 N is acting along x-axis. Its vertical component will be:

10 N

0.5 N

Zero

20 N

Fy = F Sin θ

Fy = 10 Sin 0°

Fy = 10 (0)  =   0 N

10 / 20

A body is said to be in equilibrium if:

Its acceleration is not uniform

Its acceleration is uniform

Its velocity is not changing

Its velocity is changing

11 / 20

A racing car is made stable by:

Decreasing its width

Increasing its speed  

Lowering its centre of gravity

Decreasing its mass

For stable equilibrium center of gravity must be at the lowest position.

12 / 20

Centre of gravity of a uniform triangular sheet lies at the point of intersection of its:

Medians              

Diagonals

Corners     

Lines   

13 / 20

The number of perpendicular components of a force are:

2

3

1

4

There are two perpendicular components :

Horizontal component Fx

and vertical component Fy

14 / 20

A point where the whole weight of the body appears to act vertically downward is called:

Centre of mass

Centre of gravity

Moment arm

Torque

Weight is related to gravity so correct answer is center of gravity.

15 / 20

Forces that are parallel to each other and have the same direction are called:

Unparallel forces

Like parallel forces

Parallel forces

Unlike parallel forces

Same direction means like

and opposite direction means unlike

16 / 20

When a body is in unstable equilibrium, its center of gravity:

is at the lowest position

is at its highest position

all are correct

remains at the same height

17 / 20

When a body is in neutral equilibrium, its center of gravity:

is at the lowest position

is at its highest position

remains at the same height

all are correct

18 / 20

When a body is in stable equilibrium, its center of gravity:

all are correct

is at the lowest position

is at its highest position

remains at the same height

Use formula   Fx = F Cos θ

19 / 20

If F=200N and θ=30°  with horizontal then what will be the value of F_x?

100 N

50 N 

200 N 

173.2 N 

Fx = F Cosθ

Fx = 200 × Cos 30°

Fx = 200 × 0.866

Fx = 173.2 N

20 / 20

Two equal but unlike parallel forces having different line of action produce:

a couple

equilibrium

neutral equilibrium

a torque

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