**Class 9 Physics Solved Paper 2019 Overseas**

Class 9 Physics Solved Paper 2019 Overseas for Federal Board is available in this post. You can see more FBISE solved past papers of class 9 on our website.

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**Class 9 Physics Solved Paper 2019 Overseas**

**Section A**

**Q1. MCQs **

**Class 9 Physics Solved Paper 2019 Overseas**

**Section B**

**Class 9 Physics Solved Paper 2019 Overseas**

**Q2. **

**(i) ****Define the term prefixes and write four prefixes commonly used.**

**Define the term prefixes and write four prefixes commonly used.****Ans.** **Prefixes:**

The words or letters added before a unit and stand for the multiples or submultiples of that unit are known as prefixes.

For example, kilo (k), mega (M), milli (m), and micro, etc.

**(ii) **Write the following in standard form:

a. 11.68 x 10^{-27} m

b. 32 x 10^{5 }s

c. 725 x 10^{-5} kg

**Sol. ****(a) 1168 x 10 ^{-27} m **

= 1168 x 10

^{-27}

=

**1.168 x 10**

^{-24}**(b) 32 x 10**

^{-5 }s=

^{ }32 x 10

^{-5}

=

**3.2 x 10**

^{-4}**(c) 725 x 10**

^{-5}kg= 725 x 10

^{-5}kg

= 725 x 10

^{-5}x 10

^{3 }g (k = 10

^{3})

= 725 x 10

^{-2}g

=

**7.25 g**

**(iii) ****Define gravitational acceleration. Give its SI unit and value.**

**Define gravitational acceleration. Give its SI unit and value.****Ans. Gravitational Acceleration**

The acceleration produced in a freely falling body due to the attraction of the earth is called gravitational acceleration or acceleration due to gravity. It is denoted by ‘g’.

Its SI Unit is ms^{-2 }and its value is 9.8 ms^{-2} on the surface of the earth.

**(iv) ****How are vector quantities important to us in our daily life?**

**How are vector quantities important to us in our daily life?****Ans. **Vector quantities have direction. Without direction, we cannot find the location of an object. The whole GPS system is based on location for which we need to know the direction from a particular place. Therefore, vector quantities are very important in our daily life.

**(v) ****A cyclist of mass 40 kg exerts a force of 200N to move his bicycle with an acceleration of 3ms**^{-2}. How much is the force of friction between the road and the tyres?

**A cyclist of mass 40 kg exerts a force of 200N to move his bicycle with an acceleration of 3ms**^{-2}. How much is the force of friction between the road and the tyres?**Sol. **Mass = m = 40 kg

Force = F = 200 N

Acceleration = a = 3 ms^{-2}

Force of friction = f =?

We know that

Net force = Applied Force – Force of friction

ma = F – f

or f = F – ma

f = 200 – (40) (3)

f = 200 – 120**f = 80 N**

**(vi) ****How does oiling the moving parts of a machine reduce friction?**

**How does oiling the moving parts of a machine reduce friction?****Ans.** Friction exists due to the interlocking of ups and downs on the surfaces. While oiling various parts of the machine, downs are filled with oil which makes them smooth and slippery. They can easily move against each other, and friction between them is reduced.

**(vii) ****Name three objects that work by the turning effect of forces.**

**Name three objects that work by the turning effect of forces.****Ans. **Following are the three objects that work by the turning effect of forces:

(i) Pencil Sharpener

(ii) Water tap

(iii) Doorknob

(iv) Steering wheel

**(viii) ****Why is there a need for a second condition for equilibrium if a body satisfies the first condition for equilibrium?**

**Why is there a need for a second condition for equilibrium if a body satisfies the first condition for equilibrium?****Ans.** The first condition does not ensure that a body is in equilibrium.**Example:** Consider a body is acted upon by two equal and opposite forces. Although the first condition of equilibrium is satisfied, still the body is not in equilibrium and it will rotate in the anticlockwise direction. Thus, there is a need for the second condition of equilibrium in addition to the first condition of equilibrium.** **

**(ix) ****Can you determine the mass of the moon? If yes, then what do you need to know?**

**Can you determine the mass of the moon? If yes, then what do you need to know?****Ans.** Like the mass of earth, we can also find the mass of the moon by the following equation:

M= g R^{2} / G

For this purpose, we need to know:

i) The value of ‘g’ on the moon

ii) The radius of the moon

**(x) ****On reaching the **top of a slope 6m high from its bottom, a cyclist has a **speed of 1.5 ms**^{-1}. Find the kinetic energy and the potential energy of the cyclist. The mass of the cyclist and his bicycle is 40kg.

**On reaching the**

**speed of 1.5 ms**^{-1}. Find the kinetic energy and the potential energy of the cyclist. The mass of the cyclist and his bicycle is 40kg.**Sol. **Height of slope = h = 6 m

Speed = v = 1.5 ms^{-1}Mass = m = 40 kg

Kinetic Energy = K.E =?

Potential Energy = P.E =?

Using formula for Kinetic Energy

K.E = ½ m v^{2}K.E = ½ (40) (1.5)^{2}

K.E = (20) (2.25)**K.E = 45 J**

Now using the formula for Potential Energy

P.E = m g h

P.E = (40) (10) (6)**P.E = 2400 J**

**(xI) ****What is meant by the efficiency of a system?**

**What is meant by the efficiency of a system?****Ans.** The efficiency of a system is the ratio of the required form of energy obtained from a system as output to the total energy given to it as input.

The efficiency of a machine is given by:

It is observed that the efficiency of a working system is always less than 100% because every system meets energy losses due to friction that causes heat and noise etc. However, an ideal system is that in which output energy is equal to the total energy given to it. In other words, its efficiency is 100%.

**(xiI) ****Write three features of the kinetic molecular model of matter.**

**Write three features of the kinetic molecular model of matter.****Ans.** The three features of the kinetic molecular theory are:

1. Matter is made up of particles called molecules.

2. The molecules remain in continuous motion.

3. Molecules attract each other.

**(xiiI) ****Why is water NOT suitable to be used in barometers?**

**Why is water NOT suitable to be used in barometers?****Ans.** The water is not suitable to be used in barometers, because:

1. The density of water is low (10^{3} kg m^{-3}). At sea level, the vertical height of the water column would be 10.34 m. It is impractical to have such a long tube.

2. Water sticks to the glass tube and wets it, so the reading becomes inaccurate.

**(xiv) ****Convert 100°F into the temperature on the Celsius scale.**

**Convert 100°F into the temperature on the Celsius scale.****Sol.**

**(xv) ****Briefly explain why does land breeze blows** from the land towards the **sea?**

**Briefly explain why does land breeze blows**

**sea?****Ans. ** At night, the land cools faster than the sea. Therefore, the air above the sea is warmer, rises up and the cold air from the land begins to move towards the sea. It is called land breeze.

**Class 9 Physics Solved Paper 2019 Overseas**

**Section **C

**Class 9 Physics Solved Paper 2019 Overseas**

**Q3. a. On what factors does the accuracy in measuring a physical quantity depend? (3)**

**Ans.** The accuracy in measuring a physical quantity depends upon various factors:

* The quality of the measuring instrument.

* The skill of the observer.

* The number of observations made.

**Q3. b. Derive S=V**_{i}t +½ at^{2} (4)

_{i}t +½ at

^{2}(4)

**Ans. Second Equation**S = v

_{i}t + ½ at

^{2}Consider the speed-time graph in which the initial velocity vi=OA, final velocity vf=BD, and BC=at. Also, AC=OD=t

Total distance covered

S= (Area of rectangle OACD + Area of triangle ABC)

As area of rectangle OACD = OA x OD

= vi x t = vi t

Area of triangle ABC = ½ (AC x BC)

= ½ (t x at) = ½ at^{2}As** **S = Area of rectangle OACD + Area of Δ ABC

Therefore, **S = V _{i}t + ½ at^{2}**

**Q3. a. A bullet of mass 20g is fired from a gun with a muzzle velocity 100 . Find the recoil of the gun if its mass is 5kg. (3)**

**Sol. **Mass of the bullet = m = 20 g = 20/1000 kg = 0.02 kg

Velocity of the bullet = v = 100 ms^{-1}

Mass of rifle = M = 5 kg

Velocity of rifle = V =?

According to the law of conservation of momentum:

MV + mv = 0

(5) V + (0.02) (100) = 0

5 V + 2 = 0

5 V = – 2

V = – 2 / 5**V = – 0.4 ms ^{-1}**Thus, the recoil of the gun will be – 0.4 ms

^{-1}.

**Q4. a. Differentiate between the **centre of mass and the **centre of gravity. (2)**

**Ans. Centre of mass**The Centre of mass of a system is such a point where an applied force causes the system to move without rotation.

**Centre of gravity**

A point where the whole weight of the body appears to act vertically downward is called the centre of gravity of a body.

**Q4. b. Calculate the value of g at an altitude of 1000 km. The mass of the earth is 6.0 x 10**^{24} kg. The radius of the earth is 6400km. (4)

^{24}kg. The radius of the earth is 6400km. (4)

**Sol. **Height above the Earth = h =1000 km =1000 x 1000 m = 1 x 10^{6} m

Mass of earth = M_{e} = 6.0 x 10^{24} kg

Radius of earth = R = 6.4 x 10^{6 }m

Gravitational constant = G = 6.673 x 10^{-11} Nm^{2} kg^{-2}

Acceleration due to gravity =g_{h} =?

**Q4. c. What are fossil fuels? Explain. (4)**

**Ans: **Fossil fuels are usually hydrocarbons (compounds of carbon and hydrogen). Coal, oil and gases are well-known fossil fuels. We use fossil fuels to heat our houses and run industry and transport. They are also known as nonrenewable resources because it took millions of years for them to attain their present form.

When they are burnt, they combine with oxygen from the air. The carbon becomes carbon dioxide; hydrogen becomes hydrogen oxide called water; while energy is released as heat. In the case of coal:

Carbon + Oxygen → Carbon dioxide + Heat energy

Hydrocarbon + Oxygen → Carbon dioxide + Water + Heat energy

**Q5. a. Explain the construction and working of the hydraulic press. (4)**

**Ans: Hydraulic Press**

Hydraulic Press is a machine which works on the principle of Pascal’s Law. It consists of two cylinders of different cross-sectional areas. Each cylinder is fitted with watertight pistons joined with each other by means of pipe. When a force ‘F_{1}’ is applied on a small piston of area ‘a’, the pressure produced by it is transmitted equally on the large piston. Therefore a large force ‘F_{2}’ acts on the larger piston of area ‘A’. Thus

The pressure on small piston P = F_{1} / a

The pressure on large piston P = F_{2 }/ A

Comparing the two equations

F_{2} / A = F_{1} / a

Or F_{2} = (F_{1} x A) / a

As the force F_{2} is much greater than the force F_{1}. Therefore, the Hydraulic Press systems working in this way are known as “Force multipliers”.

**Q5. b. An electric heater supplies heat at the rate of 1000 Js**^{-1}. How much time is required to raise the temperature of 200g of water from 20°C to 90°C? (3)

^{-1}. How much time is required to raise the temperature of 200g of water from 20°C to 90°C? (3)

**Sol.** Rate of heat supplied by heater = P = 1000 Js^{-1 }Mass of water = m = 200 g = 0.2 kg

Initial temperature = T_{1} = 20 °C = 20+273 = 293 K

Final temperature = T_{2} = 90 °C = 90+273=363 K

Change in temperature = ΔT = T_{2} – T_{1}= 363 – 293 = 70 K

Specific heat of water = 4200 J kg^{-1} K^{-1 }Time = t =?

Using formula

ΔQ = m c ΔT

ΔQ = 0.2 x 4200 x 70

**ΔQ = 58800 J **Now we know that

Total Heat Supplied = Rate of Heat supplied x time

ΔQ = P x t

Or t = ΔQ / P

t = 58800 / 1000

**t = 58.8 s**

**Q5. c. Which measures can be taken to save energy in houses? (3)**

**Ans.** In houses, good thermal insulation means lower consumption of fuel. For this, the following measures may be taken to save energy.

1. Hot water tanks are insulated by plastic or foam lagging.

2. Wall cavities are filled with plastic foam or wool.

3. Ceiling of rooms is covered by insulating materials (false ceiling).

4. Double glazed window panes are used. These window panes have air between glass sheets that provides good insulation.

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