Physics 10 Unit 10 MCQs Tests by admin | Class 10 MCQs Tests | 0 comments In this post, we have prepared 2 MCQs tests of Federal Board Physics 10 Unit 10 MCQs Tests. For more Class 10 Physics MCQs Tests visit this page. Physics 10 Unit 10 MCQs Tests Practice MCQs Test No 1 /9 71 Class 10 Physics Unit 10 Practice MCQs Test 1 1 / 9 Which of the following is an example of simple harmonic motion? a bouncing ball on a floor the spinning of the Earth on its axis the motion of ceiling fan the motion of simple pendulum 2 / 9 Which of the following devices can be used to produce both transverse and longitudinal waves? a ripple tank a helical spring (slinky) a tuning fork a string 3 / 9 A large ripple tank with a vibrator working at a frequency of 30 Hz produces 25 complete waves in a distance of 50 cm. The velocity of the wave is: 53 cms-1 1500 cms-1 60 cms-1 750 cms-1 4 / 9 If the mass of the bob of a pendulum is increased by a factor of 3, the period of the pendulum's motion will: be decreased by a factor of 4 be decreased by a factor of 2 remain the same be increased by a factor of 2 5 / 9 Which of the following is a method of energy transfer? all of these conduction radiation wave motion 6 / 9 Wave transfer: wavelength frequency velocity energy 7 / 9 In a vacuum, all electromagnetic waves have the same: wavelength speed frequency amplitude 8 / 9 Which of the following characteristics of a wave is independent of the others? frequency wavelength amplitude speed 9 / 9 The relation between v, f and λ of a wave is: f λ = v v = λ / f v f = λ v λ = f Your score is LinkedIn Facebook Twitter VKontakte 0% Restart quiz Send feedback Practice MCQs Test No 2 /12 54 Class 10 Physics Unit 10 Practice MCQs Test 2 1 / 12 If the length of the simple pendulum is halved its new time period ‘T’ will become: √2 T T / 2 2 T T / √2 2 / 12 If the time period of simple pendulum is one second, then its length on earth will be: 3.25 m 2.25 m 1.25 m 0.25 m 3 / 12 S.I unit of spring constant “K” is: Nm -2 Nm Nm -1 N -1 m 4 / 12 If the mass of bob of a pendulum is increased by a factor of ‘2’ then the period of pendulum motion will: Increase a factor of ‘2’ Remains same Increase a factor of ‘4’ Increase a factor of √2 5 / 12 If F=0.08N and X=4cm then value of “K” is: 4 Nm -1 0.4 Nm -1 2 Nm -1 0.2 Nm -1 6 / 12 If the length of a simple pendulum is doubled, then its new frequency f ' becomes: √2 f 2 f f / √2 f / 2 7 / 12 What is the frequency of second pendulum? 1.5 Hz 0.5 Hz 1 Hz 2 Hz 8 / 12 When a ball is gently displaced from the centre of a bowl, it starts oscillating about the centre due to: Magnetic force Force of friction Force of gravity Elastic force 9 / 12 In case of vibratory motion, time period is reciprocal of the: Wavelength Frequency Velocity Distance 10 / 12 What is the displacement of an object in simple harmonic motion when K.E=P.E? x=xo / √2 x=xo / 4 x=xo x=xo2 / 3 11 / 12 The pendulum clock was invented by: Huygens Galileo Newton Faraday 12 / 12 What is the length of second’s pendulum? 1.02 km 1.02 m 1.02 mm 1.02 cm Your score is LinkedIn Facebook Twitter VKontakte 0% Restart quiz Send feedback Submit a Comment Cancel replyYou must be logged in to post a comment.